x^2+x+1=3/4

Solution for x^2+x+1=3/4 equation:

x^2+x+1=3/4

We move all terms to the left:

x^2+x+1-(3/4)=0

We add all the numbers together, and all the variables

x^2+x+1-(+3/4)=0

We get rid of parentheses

x^2+x+1-3/4=0

We multiply all the terms by the denominator


x^2*4+x*4-3+1*4=0

We add all the numbers together, and all the variables

x^2*4+x*4+1=0

Wy multiply elements

4x^2+4x+1=0

a = 4; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·4·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-4}{8}=-1/2$